Combustion efficiency is a calculated measurement (in percent) of how well the heating equipment is converting a specific fuel into useable heat energy at a specific period of time in the operation of a heating system. Combustion test instruments evaluate these combustion gases. Complete combustion efficiency (100%) would extract all the energy available in the fuel. However, 100% combustion efficiency is not realistically achievable due to stack loss and boiler shell losses. Various combustion processes produce efficiencies from 0% to 95+%.

Tanya – EKO SUGIARTO

dear, all.

Mohon penjelasan… 1.Combustion efficiency ..? 2.Destruction efficiency ?
apakah sama istilah diatas tersebut ?dan terakhir,, destruction efficiency alat ukurnya pakai apa ?
terima kasih sebelumnya.

Tanggapan 1 – Had Had

Dear Eko

Apakah combustion efficiency yang dimaksud adalah efficiency pembakaran sebagai pemanas/heater/furnace? Jika iya mungkin itu sama dengan thermal efficiency.
Yaitu perbandingan antara panas yang diserap dengan panas yang dilepas dari hasil pembakaran.

Maaf jika kurang membantu.

Tanggapan 2 – EKO SUGIARTO

Mmg itu di flare system yang tujuanya untuk destruction sisa gas CH4 danCO2..? mmg combustion efficiency = efficiency pembakaran,,, tp rumusnya bgmn?

thx lot

Tanggapan 3 – Ginting Simeon

Dear Pak Eko,

Untuk aplikasi flare, pengertian CE dan DE adalah sbb (saya sadur dari Combustion Handbook) :

DE is a measure of how much of the original hydrocarbon is destroyed, that is, broken down into non-hydrocarbon forms, specially CO, CO2, and water vapor (H2O).

%DE = {(CO2+CO)/(CO2+CO+UHC)}x100

CO2, CO & UHC = the volume concentrations of CO2, CO, and Unburned hydrocarbons in the plume at the end of the flare flame.

Notice that if no unburned hydrocarbons escaped the flame, the DE would be 100%.

DE is a measure of how much of the original hydrocarbon burns completely to carbon dioxide and water vapor.

%DE = {CO2/(CO2+CO+UHC)}x100

Notice that even if no unburned hydrocarbons escape the flame, the CE can be less than 100% because CO represents incomplete combustion.

CE will always be less than or equal to DE.

Tanggapan 4 – EKO SUGIARTO

dear…thank’s lot your information , ..but,. i . ve question.. about your anwser, i can’t see. where is CE ( formula ) below.and what. equipment for measure (DE ).

Tanggapan 5 – Ginting Simeon

Maaf Pak Eko, typo error. Yg benar :

DE is a measure of how much of the original hydrocarbon is destroyed, that is, broken down into non-hydrocarbon forms, specially CO, CO2, and water vapor (H2O). DE can be calculated by a carbon balance as follows :

%DE = { (CO2+CO) / (CO2+ CO+UHC) } x 100

CO2, CO & UHC = the volume concentrations of CO2, CO, and Unburned hydrocarbons in the plume at the end of the flare flame.

Notice that if no unburned hydrocarbons escaped the flame, the DE would be 100%.

CE is a measure of how much of the original hydrocarbon burns completely to carbon dioxide and water vapor.

%CE = {(CO2) / (CO2+CO+ UHC) } x 100

Notice that even if no unburned hydrocarbons escape the flame, the CE can be less than 100% because CO represents incomplete combustion.

CE will always be less than or equal to DE.

Tanggapan 6 – D. Amoriza

Pak Eko,

Coba membantu, cmiiw:

Combustion efficiency is a calculated measurement (in percent) of how well the heating equipment is converting a specific fuel into useable heat energy at a specific period of time in the operation of a heating system. Combustion test instruments evaluate these combustion gases.

Complete combustion efficiency (100%) would extract all the energy available in the fuel. However, 100% combustion efficiency is not realistically achievable due to stack loss and boiler shell losses. Various combustion processes produce efficiencies from 0% to 95+%. Combustion efficiency calculations assume complete fuel combustion and are based on three factors:

1. The chemistry of the fuel (the various proportions of hydrogen, carbon, oxygen and other compounds) and how much energy is chemically bound in the fuel.

2. The net temperature of the stack gases or how much heat is not being used.

3. The percentage of oxygen (O2) or carbon dioxide (CO2) by volume after the combustion process or how much O2 did the fuel completely burn.

If your calculation shows that your equipment is losing 25% of the maximum theoretical heating value of the fuel through stack losses, your equipment is running at 75% efficient.

http://www.bacharach-training.com/combustionzone/efficiencytypes1.htm

Tanggapan 7 – EKO SUGIARTO

Dear, pa Amoriza ,

Thank’s lot atas bantuanya,

Klo boleh tanya satu lagi : alat ukur? untuk destruction efficiency pada flare system apa pa? (untuk mengetahui, bahwa hasil pembakaran flare itu sempurna ). bapak ada reff alatnya..